(i) If we consider an element of the charged surface, then the charge on the element experiences
a repulsive force due to the charge on the remaining part. As a result, a resultant force acts on
it perpendicular to the surface in the outward direction.
(ii) The charged surface behaves as a stretched membrane.
(iii) If s is the surface charge density, then the electric field intensity at external points close to the surface is (s /Î0)and at internal points close to the surface the field is zero. Thus the average intensity at the surface.
E = (s / 2Î0)
(iv) The repulsive force acting on a unit area of the surface will be.
F = Es = (s2 /2Î0)N/m2
(v) The repulsive force acts in the outwards direction. The force acting on a unit area of the surface
is electrical pressure.
\ Pelec = (s2/2Î0)
= 2pKs2 N/m2
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