ELECTRIC FIELD INTENSITY ON THE AXIS OF A UNIFORMLY CHARGED RING
Let dE be the electric field at a point P on the axis, due to charge dq, while total charge on the ring is q. then dE = (1/4pÎ0) (dq/(r2 + a2))
As only axial components of electric field due to all elements remain, while perpendicular components are
cancelled.
Therefore ‘E’ at Point P = ∫dE cosq
